Answer:
[tex]x=\dfrac{\log 6}{\log 23}[/tex]
Step-by-step explanation:
Given exponential equation:
[tex]23^x=6[/tex]
[tex]\textsf{Apply the log law}: \quad a^c=b \iff \log_ab=c[/tex]
[tex]\implies\log_{23}6=x[/tex]
[tex]\textsf{Given change of base formula}: \quad \log_by=\dfrac{\log y}{\log b}}[/tex]
Apply the given change of base formula:
[tex]\implies x=\dfrac{\log 6}{\log 23}[/tex]
