Answer:
(-2,5), refer to the step-by-step. Feel free to comment any questions you may have!
Step-by-step explanation:
Given the system of equation, [tex]\left \{ {{x+6y=28} \atop {2x-3y=-19}} \right.[/tex], solve by elimination.
[tex]\left \{ {{-2(x+6y=28)} \atop {2x-3y=-19}} \right.[/tex] , multiply the top equation by -2.
We get, [tex]\left \{ {{-2x-12y=-56} \atop {2x-3y=-19}} \right.[/tex]
[tex]+ {{-2x-12y=-56} \atop {2x-3y=-19}} \right.[/tex], add the equations together.
We get, [tex]-15y=75[/tex], we just eliminated the variable, x, we can now solve this equation for y.
[tex]-15y=-75 = > y=\frac{-75}{-15}[/tex], [tex]y=\frac{75}{15} = > y=5[/tex]
We just found the value y, which is y=5. Now we can take this value and plug it into y for either of the two original equations and solve for x. I will take the top equation...
[tex]x+6y=28 = > x+6(5)=28 = > x+30=28[/tex], subtract the value, 30, from both sides. We get, [tex]x=-2[/tex].
We found the value x, x=-2.
Thus the solution to the given system of equations is (-2,5).
