Q6.
Here is a rule for a sequence.
After the first two terms, each term is the sum of the previous two terms.
(2) (Total 4 marks)
The first five terms are p 23 q 57 r
Work out the values of p, q and r.

Respuesta :

Answer:

Step-by-step explanation:

In this sequence, the first two terms are p and q. The third term is the sum of the first two: r = p + q.

We can rearrange this equation to solve for q: q = r - p.

Substituting the given values, we have q = 57 - 23 = 34.

Now we can solve for p: p = r - q = 57 - 34 = 23.

Therefore, the values of p, q and r are p = 23, q = 34 and r = 57.

Answer:

p = 11

q = 34

r = 91

Step-by-step explanation:

If each term (after the first two terms) is the sum of the previous two terms:

[tex]\implies p+23=q[/tex]

[tex]\implies 23+q=57[/tex]

[tex]\implies q+57=r[/tex]

Solve the second equation for q:

[tex]\implies 23+q=57[/tex]

[tex]\implies 23+q-23=57-23[/tex]

[tex]\implies q=34[/tex]

Substitute the found value of q into the first equation and solve for p:

[tex]\implies p+23=34[/tex]

[tex]\implies p+23-23=34-23[/tex]

[tex]\implies p=11[/tex]

Substitute the found value of q into the third equation and solve for r:

[tex]\implies 34+57=r[/tex]

[tex]\implies r=91[/tex]

Therefore:

  • p = 11
  • q = 34
  • r = 91