Answer : The energy of exactly one photon of this light is [tex]4.64\times 10^{-19}J[/tex]
Explanation : Given,
Frequency of blue light = [tex]7.00\times 10^{14}Hz=7.00\times 10^{14}s^{-1}[/tex]
Formula used :
[tex]E=h\times \nu[/tex]
where,
[tex]\nu[/tex] = frequency of light
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
Now put all the given values in the above formula, we get:
[tex]E=(6.626\times 10^{-34}Js)\times (7.00\times 10^{14}s^{-1})[/tex]
[tex]E=4.64\times 10^{-19}J[/tex]
Therefore, the energy of exactly one photon of this light is [tex]4.64\times 10^{-19}J[/tex]
