susan took two tests.the probability of her passing both tests is 0.6.the probability of her passing the first test is 0.8.what is the probability of her passing the second test given that she has passed the first test?

formula for this is as follows:
probability of her passing both 0.6/0.8 - first test and this is a fraction. 0.6/0.8
0.6/0.8= divide 0.6 by 0.8=0.75
that means probability of her passing the second test is 75%

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Cricetus Cricetus · Answer 2 · 2021-09-25T12:03:46+02:00

"0.75" will be the probability of Susan passing her second test. A complete solution is below.

According to the question,

The probability of Susan passing her both tests,

0.6

The probability of passing 1st test,

0.8

Now,

The probability of passing her 2nd test will be:

→ [tex]P(2^{nd} \ test | 1^{st} \ test) = \frac{0.6}{0.8}[/tex]

→ [tex]= 0.75[/tex]

Thus the above approach is right.

Learn more about the probability here:

https://brainly.com/question/3066523