Answer: The probability that the fourth marble Amy picks is black [tex]=\frac{8}{15}[/tex]
The probability that in the fifth attempt she will pick a red or a black marble P(R∩B) =[tex]\frac{5}{7}[/tex]
Step-by-step explanation:
To find the probability that in the fifth attempt she will pick a red or a black marble P(R∩B) .
The total marble in beginning=6+4+8=18
After 3 attempts, the total marbles left=18-3=15
The number of black marbles =8
The probability that the fourth marble Amy picks is black [tex]=\frac{8}{15}[/tex]
As four marble has already picked up, then the total marbles left in the box
=18-4=14
Now, as a red marble is already picked in 1st attempt , the number of red marbles in the box now= 4-1=3
And a black marble is already picked in fourth attempt , the number of black marbles in the box now= 8-1=7
Now P(R∩B)=P(R)+P(B)=[tex]\frac{3}{14}+\frac{7}{14}=\frac{10}{14}=\frac{5}{7}[/tex]
Answer:
The probability that the fourth marble Amy picks is black is 8/15. If Amy picks a black marble in the fourth attempt, the probability that in the fifth attempt she will pick a red or a black marble is 5/7
Step-by-step explanation:
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