Let f(x)=x2+3x−4 .

What is the average rate of change for the quadratic function from x=−3 to x = 8?


Let f(x)=−14(x+4)2−8 .

What is the average rate of change for the quadratic function from x=−2 to x = 2?


Which function grows at the fastest rate for increasing values of x?



f(x)=4⋅2x

h(x)=9x2+25

g(x)=15x+6


Respuesta :

Answer:

f(x) = 4 · 2^x is the correct answer for Which function grows at the fastest rate for increasing values of x?

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Answer:

1) The average rate of change is 8.

2) The average rate of change is 112.

3) f(x) grows at the fastest rate.

Step-by-step explanation:

1) Given : Function [tex]f(x)=x^2+3x-4[/tex]

To find : What is the average rate of change for the quadratic function from x=−3 to x = 8?

Solution :

The average rate of change is [tex]A_v=\frac{f(b)-f(a)}{b-a}[/tex]

Where, a=-3 and b=8

[tex]A_v=\frac{((8)^2+3(8)-4)-((-3)^2+3(-3)-4)}{8-(-3)}[/tex]

[tex]A_v=\frac{(84)-(-4)}{11}[/tex]

[tex]A_v=\frac{88}{11}[/tex]

[tex]A_v=8[/tex]

The average rate of change is 8.

2) Given : Function [tex]f(x)=-14(x+4)^2-8[/tex]

To find : What is the average rate of change for the quadratic function from x=−2 to x = 2?

Solution :

The average rate of change is [tex]A_v=\frac{f(b)-f(a)}{b-a}[/tex]

Where, a=-2 and b=2

[tex]A_v=\frac{(-14(2+4)^2-8)-(-14(-2+4)^2-8)}{-2-2}[/tex]

[tex]A_v=\frac{(-512)-(-64)}{-4}[/tex]

[tex]A_v=\frac{-448}{-4}[/tex]

[tex]A_v=112[/tex]

The average rate of change is 112.

3) To find : Which function grows at the fastest rate for increasing values of x?

Solution :

1) [tex]f(x)=4\cdot2^x[/tex] is an exponential function.

2) [tex]h(x)=9x^2+25[/tex] is a quadratic function.

3) [tex]g(x)=15x+6[/tex] is a linear function.

Increasing values of x will increase exponentially.

So, it will grow at the fastest rate.

f(x) grows at the fastest rate.