Respuesta :
we know that 0.75d=(s^2)/(30.25) , so for d=140ft
0.75 x 140= (s^2)/(30.25) implies 0.75 x 140 x 30.25)= (s^2), and then
s= sqrt( 0.75 x 140 x 30.25)=56.35 miles /hour
0.75 x 140= (s^2)/(30.25) implies 0.75 x 140 x 30.25)= (s^2), and then
s= sqrt( 0.75 x 140 x 30.25)=56.35 miles /hour
The approximate speed of a vehicle that left a skid mark measuring 140 feet is 56.35 miles per hour.
Let, s is the speed in miles per hour,
And d is the length of the vehicle’s skid marks.
The brakes are applied using the formula
[tex]0.75d = \frac{s^{2}}{30.25}[/tex]
We have to find,
The approximate speed of a vehicle that left a skid mark measuring 140 feet.
According to the question,
[tex]0.75d = \frac{s^{2}}{30.25}[/tex]
= 0.75d = [tex]\frac{s^{2}}{30.25}[/tex] ,
So, for d = 140ft
= 0.75 x 140 = [tex]\frac{s^{2}}{30.25}[/tex]
= 0.75 x 140 x 30.25) = [tex]s^{2}[/tex],
s = [tex]\sqrt{(0.75).(140).(25)}[/tex] = 56.35 miles per hour
Hence, The approximate speed of a vehicle that left a skid mark measuring 140 feet is 56.35 miles per hour .
For more information about Velocity click the link given below.
https://brainly.com/question/17127206