HELP PLEASE!!
1) the probability distribution table shows the proportion of people living in the five different regions of a city. there are now 46,700 residents in the city. how many live in the west region?
A)467
B)934
C)2335
D)9340

2)The probability distribution table shows the proportion of people living in the five different regions of a city. What is the probability that a person chosen at random, who lives in the city, lives in the central or south region?
A)0.58
B)0.44
C)0.3
D)0.14

Question

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Respuesta :

frika frika · Answer 1 · 2018-11-21T12:00:03+01:00

1. The probability distribution table shows the proportion of people living in the five different regions of a city.

The probabiliy that a person randomly selected lives in the west region is 0.2. Let x be the number of people that live in the west region. Then

[tex]\dfrac{x}{46,700}=0.2,\\ \\x=46,700\cdot 0.2=9,340.[/tex]

Answer 1: correct hcoice is D

2. The probability that a person chosen at random lives in the central or south region is

[tex]Pr(\text{central or south})=Pr(\text{central})+Pr(\text{south})=0.44+0.14=0.58.[/tex]

Answer 2: correct choice is A

Cricetus Cricetus · Answer 2 · 2021-10-28T11:56:37+02:00

The number of people will be "9340". The probability will be "0.58".

(1)

According to the question,

Number of residents,

The probability of residents in west region,

The number of people will be:

= [tex]Number \ of \ residents\times probability[/tex]

= [tex]46,700\times 0.2[/tex]

= [tex]9340[/tex]

(2)

According to the question,

Probability of central,

Probability of south,

The probability of chosen people lives in central or south will be:

= [tex]Probability \ of \ central+Probability \ of \ south[/tex]

= [tex]0.44+0.14[/tex]

= [tex]0.58[/tex]

Thus the above answers are correct,

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