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The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?

When Harold wrote his equation, the point he used was (7, 3).
When Harold wrote his equation, the point he used was (0, 7).
When Harold wrote his equation, the point he used was (7, 0).
When Harold wrote his equation, the point he used was (3, 7).

Respuesta :

isyllus

Answer:

"When Harold wrote his equation, the point he used was (7, 0)"

Option C is correct.

Step-by-step explanation:

Given: Harold correctly wrote the equation y = 3(x – 7) using a point and the slope.

The equation of a linear function in point-slope form is [tex]y-y_1=m(x-x_1)[/tex]

We will compare the Harold equation with point-slope form

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-0=3(x-7)[/tex]

If we compare the equation we get

[tex]y_1\rightarrow 0[/tex]

[tex]x_1\rightarrow 7[/tex]

[tex]m\rightarrow 3[/tex]

Harold use the point (7,0) and slope 3.

Hence, The correct option is C. "When Harold wrote his equation, the point he used was (7, 0)"

Answer:

c

Step-by-step explanation:

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