Respuesta :

sdmatera
First we can find the perimeter of the given rectangle

P=2L+2W (L=length and W=width)
P=2*3+2*4
P=6+8
P=14

So now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let's make out width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length

14=2L+2*2
14=2L+4 
10=2L (subtract 4 from both sides)
L=5

So the dimensions are 5 units and 2 units

Hope this helps!

Answer:

First we can find the perimeter of the given rectangle

P=2L+2W (L=length and W=width)

P=2*3+2*4

P=6+8

P=14

So now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let's make out width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length

14=2L+2*2

14=2L+4

10=2L (subtract 4 from both sides)

L=5

So the dimensions are 5 units and 2 units

Step-by-step explanation:

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