Consider the Reaction: 2 NaCl + BaSO₄ → Na₂SO₄ + BaCl₂
Here, Given mass of NaCl = 3.59 g
Molar mass of NaCl = 58 g/mol
Number of moles of NaCl = 2 (3.59 / 58) = 2(0.0618) = 0.123 mol
Now, for every 2 moles of NaCl, 1 mole of Na₂SO₄ formed.
So, number of moles of Na₂SO₄ = 0.123/2 = 0.0618
In short, Your Answer would be: 0.0618 moles
Hope this helps!
