Step-by-step explanation:
A) having a blue first has a 1 out of 5 chance
then lets say you got the 1/5, after that getting an X
gives you a 1/3 probability, you can multiply then to find
x and a blue probability is 1/5 * 1/3 meaning you have
1/15 chance to get a blue x
O) there is 3/5 chance not to get red since there are 2 reds
then again you have a 1/3 chance of getting an x
giving you 3/5 * 1/3 meaning 1/5 chance to get
not red and x
for prove you can write all possibilities
blue x, blue y, blue y
white x, white y, white y
white x, white y, white y
red x, red y, red y
red x, red y, red y
meaning 15 possible outcomes in which
blue y, white x or red x have 2/15 probability
red y or white y have a 4/15
leaving blue x with a 1/15 probability
you can apply the same rule with the rest
however if the question is something like probability of orange z, or anything not mentioned its automatically 0/ all possible outcomes, or if its like not orange and not z, its 15/15 then, how ever if its not orange and y its all the Ys meaning 10/15
you just have to understand the question
like lemme try question 2 , W
probability of not white is 3/4 scince there is only 1 white and other aren't and getting an odd is 3/6 or 1/2, multiplying them you get 3/8
all outcomes
w = white
nw = not white
nw1 , nw2 , nw3 , nw4 , nw5 , nw6 6
nw1 , nw2 , nw3 , nw4 , nw5 , nw6 6
nw1 , nw2 , nw3 , nw4 , nw5 , nw6 6
w1 , w2 , w3 , w4 , w5 , w6 6 = 24
9/total outcomes = 9/24 or back to 3/8
