Natasha holds the two ends of a string in her hands and then moves her hands up and down so that a wave travels from one end of the string to the other end. In which case will she have a standing wave along the string?

A. The resultant wave rises and falls in amplitude over time and has a frequency equal to that of the waves.

B. The resultant wave has a fixed amplitude and a frequency twice that of the waves.

C. The resultant wave has a fixed amplitude and a frequency equal to that of the waves.

D. The resultant wave rises and falls in amplitude over time and has a frequency twice that of the waves.

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qwertyuiop13 qwertyuiop13 · Answer 1 · 2017-03-07T05:37:44+01:00

The awnser to this question is B

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aristocles aristocles · Answer 2 · 2019-04-19T01:55:58+02:00

Answer:

C. The resultant wave has a fixed amplitude and a frequency equal to that of the waves.

Explanation:

When a wave superimpose with its own reflected wave then the resultant two waves will form a standing wave

so here let say the two waves are

[tex]y_1 = Asin(\omega t - kx)[/tex]

[tex]y_2 = A sin(\omega t + kx)[/tex]

now by superposition principle of above two waves

[tex]y = y_1 + y_2[/tex]

[tex]y = Asin(\omega_1t - kx) + A sin(\omega_2t + kx)[/tex]

[tex]y = 2Acos(kx)sin(\omega t)[/tex]

so above is the resultant standing wave equation in which frequency will remain same and amplitude is fixed or constant