Respuesta :
If we let x and y be the number of books in each of the shelves, respectively. Then, we generate the equation that best shows the scenario as the following system of linear equations.
x + y = 55
x + 0.5y = 4(0.5y)
Solving for the values of x and y will give us the answers of,
x = 33
y = 22
Then, the number of books in each shelves are 33 and 22, respectively.
x + y = 55
x + 0.5y = 4(0.5y)
Solving for the values of x and y will give us the answers of,
x = 33
y = 22
Then, the number of books in each shelves are 33 and 22, respectively.
Answer:
Books in shelf one are 33 and in shelf two are 22.
Step-by-step explanation:
Let the two shelves contain x and y books.
So from first statement of the question
x + y = 55-------------(1)
[tex]\frac{y}{2}+x=4(\frac{y}{2})[/tex]
y + 2x = 4y
3y = 2x ⇒ [tex]x=\frac{3}{2}y[/tex]-------(2)
Now we put the value of x from equation 2 to equation 1
[tex]\frac{3}{2}y+y=55[/tex]
[tex]\frac{5}{2}y=55[/tex]
y = 22
Since x + y = 55 ⇒ 22 + x = 55
x = 33
So shelf one is having 33 books and shelf two is having 22 books.