Answer: P( Cream and Sugar) = 0.4
Step-by-step explanation:
Since we have given that
P(Cream)=0.5
P(Sugar)=0.6
P(Cream or Sugar)=0.7
As we know the " Probability Rules" so, we get,
[tex]P(Cream\ and\ Sugar)=P(Cream)+P(Sugar)-P(Cream\ or\ Sugar)\\\\P(C\cap S)=P(C)+P(S)-P(C\cup S)\\\\P(C\cap S)=0.5+0.6-0.7\\\\P(C\cap S)=1.1-0.7\\\\P(C\cap S)=0.4[/tex]
So, P( Cream and Sugar) = 0.4
The value of P(cream and sugar) is 0.4.
Given
A diner has collected data about customer coffee-drinking habits.
They have calculated that P(cream) = 0.5, P(sugar) = 0.6, and P(cream or sugar) = 0.7.
Two sets are non-mutually exclusive if they share common elements.
The formula is used to find non mutually exclusive probability is;
[tex]\rm P(A\ or \ B) = P(A) + P(B) - P(A \ and\ B)[/tex]
Substitute all the values in the formula;
[tex]\rm P(cream\ or \ sugar) = P(cream) + P(sugar) - P(cream \ and \ sugar)\\\\0.7 = 0.5 + 0.6 - P(cream \ and \ sugar)\\\\ P(cream \ and \ sugar)= 1.1-0.7\\\\ P(cream \ and \ sugar)=0.4[/tex]
Hence, the value of P(cream and sugar) is 0.4.
To know more about Non mutually exclusive probability click the link given below.
https://brainly.com/question/13093841
