1. Solve for x in 4x-2y+7=33
4x-2y+7=33
4x+6=33+2y
4x=33+2y-7
4x=2y+26
x=(2y+26)/4
x=(2(y+13))/4
x=(y+13)/2
2. Substitute x=(y+13)/2 into 5y=3x-30
5y=3x-30
5y=3*(y+13)/2 -30
5y=(3(y+13))/2 - 30
3. Solve for y in 5y=(3(y+13)/2 -30
5y=(3(y+13))/2 - 30
10y=3(y+13)-60
10y=3y+39-60
10y=3y-21
10y-3y=-21
7y=-21
y=-21/7
y=-3
4. Substitute y=-3 into x=(y+13)/2
x=(y+13)/2
x=(-3+13)/2
x=5
5. Therefore,
x=5 and y=-3
I hope you have a nice day :D