Respuesta :
(x^2 - 9)(x^2 + 4) the second sign gives the plus and minus signs in the factors. The 9 and 4 have the difference of 5
Answer: x^4 + 5x^2 - 36 = 0
Let u = x^2 and this becomes:
(x^2)^2 + 5(x^2) - 36 = 0
==> u^2 + 5u - 36 = 0
==> (u + 9)(u - 4) = 0
Sub back in x^2
==> (x^2 + 9)(x^2 - 4) = 0
==> (x^2 + 9)(x + 2)(x - 2) = 0
==> x = ± 3i, x = -2, and x = 2
Therefore, the solutions are 3i, -3i, 2 and -2.
I hope that helps!
Let u = x^2 and this becomes:
(x^2)^2 + 5(x^2) - 36 = 0
==> u^2 + 5u - 36 = 0
==> (u + 9)(u - 4) = 0
Sub back in x^2
==> (x^2 + 9)(x^2 - 4) = 0
==> (x^2 + 9)(x + 2)(x - 2) = 0
==> x = ± 3i, x = -2, and x = 2
Therefore, the solutions are 3i, -3i, 2 and -2.
I hope that helps!