Respuesta :

jaypee648590
Center would be (-0.2,-0.1)


and the radius is square root of 0.3 or (0.3)^1/2 [tex] \sqrt{0.3} [/tex]

Answer with explanation:

The equation of circle is :

 [tex]\rightarrow(x+0.2)^2 + (y+0.1)^2 = 0.3\\\\\rightarrow (x-(-0.2))^{2}+(y-(-0.1))^2=(\sqrt{0.3})^2\\\\\text{Equation of circle having center (a,b) and radius r is}\\\\(x-a)^2+(y-b)^2=r^2[/tex]

Center = (-0.2, -0.1)

Radius =√0.3

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