Respuesta :
Expression: t=2(2h/32)^1/2
Squaring on both sides,
t² = 2(2h/32)
t² = 4h/32
t² = h/8
h = 8t²
Height of player 1 = 8(0.9)² = 6.48 Feet
Height of player 2 = 8(0.8)² = 5.12 Feet
Difference = 6.48 - 5.12= 1.36 Feet = 16.32 in
In short, Your Answer would be:16 Inches
Hope this helps!
Squaring on both sides,
t² = 2(2h/32)
t² = 4h/32
t² = h/8
h = 8t²
Height of player 1 = 8(0.9)² = 6.48 Feet
Height of player 2 = 8(0.8)² = 5.12 Feet
Difference = 6.48 - 5.12= 1.36 Feet = 16.32 in
In short, Your Answer would be:16 Inches
Hope this helps!
The difference in jump of both players can be calculated by solving the given equation for [tex]h[/tex].
The player-1 jump 8.00 inch higher than the player-2.
Given:
The hang time equation is [tex]t=2\left(\dfrac{2h}{32}\right)^\frac{1}{2}[/tex]
Player 1 hang time is [tex]0.9\:\rm s[/tex].
Player 2 hang time is [tex]0.8\: \rm s[/tex].
Consider the given equation.
[tex]t=2\left(\dfrac{2h}{32}\right)^\frac{1}{2}[/tex]
Now, solve for the [tex]h[/tex].
[tex]t=2\left(\dfrac{2h}{32}\right)^\frac{1}{2}\\t=2\left(\dfrac{h}{16}\right)^\frac{1}{2}\\t=2\left(\dfrac{\sqrt{h} }{\sqrt{16}}\right)\\t=2\left(\dfrac{\sqrt{h} }{4}}\right)\\t=\left(\dfrac{\sqrt{h} }{2}}\right)\\h=2t^2[/tex]
Calculate the height for Player 1.
[tex]h=2\times 0.9^2\\h=3.24 \:\rm feet\\h=38.88 \;\rm in[/tex]
Calculate the height for Player 2.
[tex]h = 4(0.8)^2\\h= 2.56\:\rm feet\\h=30.72\:\ in[/tex]
Calculate the difference in jump of both players,
[tex]= 38.88 - 30.72 = 8.16[/tex]
Thus, the player-1 jump 8.00 inch higher than the player-2.
Learn more about height here:
https://brainly.com/question/12019427
