Answer: 16
Step-by-step explanation:
Given: A jar contains [tex]24[/tex] pennies. The pennies are taken out and divided into [tex]2[/tex] piles. If the larger pile contains twice as many pennies as the smaller one.
To Find: how many pennies are in the larger pile.
Solution:
Total number of pennies in the jar [tex]=24[/tex]
let the number of pennies in bigger pile [tex]=\text{x}[/tex]
let the number of pennies in smaller pile [tex]=\text{y}[/tex]
Now,
[tex]\text{x}+\text{y}=24[/tex]
as [tex]\text{x}=2\text{y}[/tex]
[tex]2\text{y}+\text{y}=24[/tex]
[tex]3\text{y}=24[/tex]
[tex]\text{y}=8[/tex]
[tex]\text{x}=2\text{y}[/tex]
[tex]\text{x}=2\times8[/tex]
[tex]\text{x}=16[/tex]
Hence there are [tex]16[/tex] pennies in larger pile.
