Squares are built at the sides of the rectangle. The area of one square is 95 cm2 greater that the area of the other square. Find the perimeter of the rectangle if the length of it is 5 cm greater than its width.

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length = w+5

width = w

Area = width × length 95

95

w=8

95 <8. (8+5)

95 <8.13

95 <104

Perimeter =2 (width +length )

Perimeter =2. (8+13)

Perimeter =42

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Dragonflyglider Dragonflyglider · Answer 2 · 2020-02-13T02:21:30+01:00

Dragonflyglider Dragonflyglider

13-02-2020

Answer:

38 cm

Step-by-step explanation:

The large square = y+95

Smaller square = y

rectangle width = x

rectangle length = x+5

Area of large square: (x+5)^2=y+95

Area of small square: x^2 = y

After some algebra: x=7, y=49

Length of rectangle: 7+5 = 12

Width of rectangle: x = 5

Perimeter = 2(12) + 2(5) = 38 cm

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￼ Squares are built at the sides of the rectangle. The area of one square is 95 cm2 greater that the area of the other square. Find the perimeter of the rectangle if the length of it is 5 cm greater than its width.

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Squares are built at the sides of the rectangle. The area of one square is 95 cm2 greater that the area of the other square. Find the perimeter of the rectangle if the length of it is 5 cm greater than its width.