Answer:
Complete factorization of 3a²+5a-12 is:
(3a-4)(a+3)
Step-by-step explanation:
We have to factorize the expression:
3a²+5a-12
3a²+5a-12=3a²+9a-4a-12 (by splitting the middle term)
=3a(a+3)-4(a+3)
= (3a-4)(a+3)
⇒ 3a²+5a-12=(3a-4)(a+3)
Hence, Complete factorization of 3a²+5a-12 is:
(3a-4)(a+3)
Answer:
Applying factor polynomials, you will find:
[tex]3a^2+5a-12=\left(3a-4\right)\left(a+3\right)[/tex]
Step-by-step explanation:
The exercise presents the equation: [tex]3a^{2} + 5a - 12[/tex].
For factoring an equation, you should write the given equation in factors. Therefore, for solving this exercise, you need to find the factors.
[tex]3a^2+5a-12= 3a^2-4a+5a-12[/tex]
2. After that, you should break the expression in groups.
[tex]3a^2-4a+5a-12= (3a^2-4a)+(9a-12)[/tex]
3. Next step, you should factor out each term. For the first factor use a and the second factor use 3.
[tex](3a^2-4a)+(9a-12)= a(3a-4)+3(3a-4)[/tex]
Here it is possible to see that [tex](3a-4)[/tex] is a factor common.
4. Finally, factor out [tex]\left(3a-4\right)\[/tex] in previous expression.
[tex]\left(3a-4\right)\left(a+3\right)[/tex]
Thus, [tex]3a^2+5a-12=\left(3a-4\right)\left(a+3\right)[/tex].
Learn more about factor an expression here:
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