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how many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 340 K?

Respuesta :

dexteright02
Data:

P (pressure) = 2.3 atm
V (volume) = 120 L
T (temperature) = 340 K
n (number of mols) = ?
R (Gas constant) = 0.082 (atm*L/mol*K)

Formula: 

[tex]p*V = n*R*T[/tex]

Solving:
[tex]p*V = n*R*T[/tex]
[tex]2.3*120 = n*0.082*340[/tex]
[tex]276 = 27.88n[/tex]
[tex]27.88n = 276[/tex]
[tex]n = \frac{276}{27.88} [/tex]
[tex]n = 9.89956...\to \boxed{\boxed{n\approx 9.90\:mols}}\end{array}}\qquad\quad\checkmark[/tex]


nuhulawal20

The amount of gas that will occupy the volume at the given pressure and temperature is 9.89moles.

Given the data in the question;

  • Volume of gas; [tex]V = 120L[/tex]
  • Pressure; [tex]2.3atm[/tex]
  • Temperature; [tex]T = 340K[/tex]
  • Amount of gas; [tex]n = \ ?[/tex]

Ideal Gas Law

The Ideal Gas Law states that "the pressure P multiply by the volume V is equal to moles multiply by temperature and the universal gas constant. It is expressed;

[tex]PV = nRT[/tex]

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( [tex]0.08206 Latm/molK[/tex] )

We substitute our values into the expression above to determine the amount of gas n.

[tex]PV = nRT\\\\2.3atm * 120L = n * 0.08206Latm/molK * 340K\\\\276Latm = n * 27.9004 Latm/mol\\\\n = \frac{276Latm}{27.9004 Latm/mol}\\ \\n = 9.89moles[/tex]

Therefore, the amount of gas that will occupy the volume at the given pressure and temperature is 9.89moles.

Learn more about Ideal Gas Law here: brainly.com/question/4147359

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