Adult tickets to the fall play cost $8 and student tickets cost $4. The drama class sold 30 more adult tickets than student tickets to the fall play. If the class collected $840 from ticket sales, how many adult tickets were sold?

Respuesta :

there was approximatly 80 adult tickets sold

The number of adult tickets sold is 80.

Given to us

  • Price of adult tickets = $8,
  • Price of student tickets = $4,  
  • Total earning from all the tickets = $840,
  • The drama class sold 30 more adult tickets than student tickets to the fall play.

Assumption

Let's assume that the number of adult tickets sold is x, and the number of student tickets sold is y.

Number of tickets sold

The drama class sold 30 more adult tickets than student tickets to the fall play. therefore,

[tex]x-y=30[/tex]

solving the equation for y,

[tex]x-y=30\\-y=30-x\\y=x-30[/tex]

Total earning through adult tickets

Total earning through adult tickets

                                     = Price of adult tickets x Number of adult tickets sold

                                     [tex]= \$8 \times x\\=8x[/tex]

Total earning through student tickets

Total earning through student tickets

                            = Price of student tickets + Number of student tickets sold

                           [tex]= \$4 \times y\\=4y[/tex]

Total earning from all the tickets

Total earning from all the tickets

= Total earning through adult tickets +Total earning through student tickets

[tex]840= 8x+4y\\[/tex]

Substituting the value of y,

[tex]840= 8x+4(x-30)\\840 = 8x +4x-120\\840+120=8x+4x\\960=12x\\12x=960\\\\x=\dfrac{960}{12}\\\\x= 80[/tex]

Hence, the number of adult tickets sold is 80.

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