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How much current is in a circuit that includes a 9.0-volt battery and a bulb with a resistance of 4.0 ohms?

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wboast
2.25 amperes

Ohms law dictates that electrical voltage = current times resistance. Since you are given voltage and not the current, you will be dividing voltage by the resistance.

9.0V ÷ 4.0ohms = 2.25 amps

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Ohm law : V=IR

            V = 9 volt

            R = 4 ohms

  I = V / R

    = 9 / 4

    = 2.25 amps

What is ohms law ?

"The strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit."

Know more about ohms law here

https://brainly.com/question/12372387

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