PLEASE

The measures in the table describe the ages of students in a club.
Mean Median Mode Mean Absolute Deviation
13.3 13.5 14 0.67

Select from the drop-down menus to correctly complete each statement.
On average, the age of a student is about (?) year(s) away from (?) year(s).

If the MAD for another club was 1.5 years, then that club's ages would be (?) than the ages for this club.

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Sharkaustin Sharkaustin · Answer 1 · 2017-05-10T08:00:34+02:00

On average, the age of a student is about .67 year(s) away from 13.3 year(s).

If the MAD for another club was 1.5 years, then that club's ages would be 3 more variable than the ages for this club.

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eudora eudora · Answer 2 · 2019-03-13T13:10:26+01:00

Answer:

Answer would be 0.67 years, 13.3 years and 1.5 years.

Step-by-step explanation:

It is given Mean = 13.3, Median = 13.5, Mode = 14, MAD = 0.67

Now we complete each statement from the given data.

Here Mean absolute Deviation is 0.67 which shows how far or how near the values to the mean value.

1. On average, the age of a student is about 0.67 year(s) away from 13.3 year(s).

2. If the MAD for another club was 1.5 years, then that club's ages would be 1.5 than the ages for this club.