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08-03-2017
Chemistry

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23 grams of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.

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xxkkxx2029 xxkkxx2029

08-03-2017

NaOH + HCl --> NaCl + H2Oso here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.Number of HCl moles Concentration of the solution = 2.00M = 2 mol/ literVolume of the solution = 22.4 mlNumber of HCl moles = (2mol/1000 ml)*22.4 ml = 0.0448 mol

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raspberry123 raspberry123

08-03-2017

NaOH + HCl --> NaCl + H2Oso here 1 mole of NaOH reacts with 1 mole of HCl. Hence it is required to convert the amount of HCl and NaOH in to moles.Number of HCl moles Concentration of the solution = 2.00M = 2 mol/ literVolume of the solution = 22.4 mlNumber of HCl moles = (2mol/1000 ml)*22.4 ml = 0.0448 mol

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