Respuesta :
Hello here is a solution :
(f-g)(x) =f(x) - g(x)
= (4x²-3)-(x+1)
= 4x² -x -4 ( answer :D)
(f-g)(x) =f(x) - g(x)
= (4x²-3)-(x+1)
= 4x² -x -4 ( answer :D)
Answer:
Option D is correct
The value of [tex](f-g)(x)[/tex] is, [tex]4x^2-x-4[/tex]
Step-by-step explanation:
Given the function:
[tex]f(x) = 4x^2-3[/tex]
[tex]g(x) = x+1[/tex]
We have to find [tex](f-g)(x)[/tex]
[tex](f-g)(x) = f(x)-g(x)[/tex]
Substitute the given functions we have;
[tex](f-g)(x) = 4x^2-3-x-1[/tex]
⇒[tex](f-g)(x)=4x^2-x-4[/tex]
Therefore, the value of [tex](f-g)(x)[/tex] is, [tex]4x^2-x-4[/tex]