Respuesta :

Data:
[tex]P_{1} = 3.4\:atm[/tex]
[tex]T_{1} = 713\:K[/tex]
[tex]P_{2} = ?[/tex]
[tex]T_{2} = 273\:K[/tex]

Formula:
[tex] \frac{ P_{1} }{ T_{1} } = \frac{ P_{2} }{ T_{2} } [/tex]
Product of extremes equals product of means
[tex] P_{1} * T_{2} = P_{2} * T_{1} [/tex]

Solving:
[tex] P_{1} * T_{2} = P_{2} * T_{1} [/tex]
[tex]3.4*713 = P_{2} * 273[/tex]
[tex]2424.2 = 273P_{2}[/tex]
[tex]273P_{2} = 2424.2[/tex]
[tex]P_{2} = \frac{2424.2}{273} [/tex]
[tex]\boxed{\boxed{P_{2} \approx 8.87\:atm}}\end{array}}\qquad\quad\checkmark[/tex]