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PLEASE HELP LAW OF COSINES

Find the measure of J, the smallest angle in a triangle with sides measuring 11, 13, and 19. Round to the nearest whole degree.

30°
34°
42°
47°

PLEASE HELP LAW OF COSINES Find the measure of J the smallest angle in a triangle with sides measuring 11 13 and 19 Round to the nearest whole degree 30 34 42 4 class=

Respuesta :

The Law of Cosine states
cos[tex]C=(a^2+b^2-c^2)/2ab[/tex]

so plugging in the numbers gives us

cos[tex]J=(13^2+19^2-11^2)/2(13*19) = 409/494[/tex]

We now have cosJ so plug that into your calculator and find arccos (arccos(cos(J)) = J)
arccos[tex](409/494)=34.11[/tex]
rounding your answer will give you 34°

Answer:

34 degrees

Step-by-step explanation:

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