Data:
Q (Amount of heat) = 832 J
m (mass) = ?
c (Specific heat) = 0.90 J/(g × ° C)
T (final) = 97 ºC
To (initial) = 20 ºC
ΔT = T - To → ΔT = 97 - 20 → ΔT = 77 ºC
Formula:
Q = m*c*ΔT
Solving:
Q = m*c*ΔT
832 = m*0.90*77
832 = 69.3m
69.3m = 832
[tex]m = \frac{832}{69.3} [/tex]
[tex]\boxed{\boxed{m \approx 12.00\:g}}\end{array}}\qquad\quad\checkmark[/tex]
