Respuesta :

[tex]\bf 9x+y=10\qquad \begin{cases} x=rcos(\theta)\\ y=rsin(\theta) \end{cases}\quad thus\quad 9rcos(\theta)+rsin(\theta)=10 \\\\\\ \textit{polar equations are in }\theta\textit{ terms, thus} \\\\\\ r[9cos(\theta)+sin(\theta)]=10\implies r=\cfrac{10}{9cos(\theta)+sin(\theta)}[/tex]