Identify the translation rule on a coordinate plane that verifies that square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-3,4), B'(-3,9), C'(-8,4), D'(-8,9) are congruent.

A)
(x, y) → (x - 1, y - 1)

B)
(x, y) → (x - 1, y + 1)

C)
(x, y) → (x + 1, y + 1)

D)
the squares are not congruent

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Аноним Аноним · Answer 1 · 2017-03-11T21:28:00+01:00

Note that each x value increases by 1 and y values also increases by 1

C is the correct option

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virtuematane virtuematane · Answer 2 · 2019-03-11T06:21:07+01:00

The translation rule is:

Option: C

(x, y) → (x + 1, y + 1)

We are given the vertices of a square A(-4,3), B(-4,8), C(-9,3), D(-9,8) and square A'(-3,4), B'(-3,9), C'(-8,4), D'(-8,9) .

We have to find the translation rule on a coordinate plane that verifies that square ABCD is congruent to square A'B'C'D'.

Since, the two squares o be congruent every vertex must be translated by the same rule.

So, the rule is:

(x, y) → (x + 1, y + 1)

since,

A(-4,3) → A'(-4+1,3+1)=A'(-3,4)

B(-4,8) →B'(-4+1,8+1)=(-3,9)

C(-9,3) → C'(-9+1,3+1)=(-8,4)

and D(-9,8) → D'(-9+1,8+1)=(-8,9)

Hence, the translation rule is:

Option: C

(x, y) → (x + 1, y + 1)