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Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

6-inch side.

A = sq. in.

Respuesta :

bcalle
A= (1/2) b*h
h=3 sqrt3
A= (1/2)*6*3sqrt3
A= 9sqrt3 square inches

Answer:

The area of the triangle is 9√3 in²

Step-by-step explanation:

We know that, the area of an equilateral triangle is,

[tex]A=\frac{\sqrt{3}}{4}a^2[/tex]

Where, a is the side of the triangle,

Given,

a = 6 inches,

Thus, the area of the given equilateral triangle is,

[tex]A=\frac{\sqrt{3}}{4}(6)^2[/tex]

[tex]=\frac{36\sqrt{3}}{4}[/tex]

[tex]=9\sqrt{3}\text{ square inches}[/tex]

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