Answer:
P( that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle)= 40/49
Step-by-step explanation:
we have to find the probability that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle.
Area of the whole figure= area of larger circle
= π×14×14 cm²
= 196π cm²
Area of the region inside the larger circle and outside the smaller circle
= area of larger circle- area of smaller circle
= π×14×14-π×6×6
= 160π cm²
P( that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle)
= area of the favorable region/area of whole figure
= 160π/196π
= 40/49
