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△DEF is similar to △JKL . In addition,  m∠F=90° and m∠K=5(m∠D)

What is m∠D?
 TRIANGLE IMAGE IS ATTACHED
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ONLY ANSWER IF YOU KNOW THE ANSWER JUST FOR POINTS Thank you worth extra points DEF is similar to JKL In addition mF90 and mK5mD What is mD TRIANGLE IMAGE IS AT class=

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nobillionaireNobley
Since triangle DEF = triangle JKL, m<D = m<J, m<E = m<K, m<F = m<L.
m<F = m<L = 90 degrees
m<K = m<E = 5(m<D)
but m<E + m<D = 90 degrees        [right angled triangle]
5(m<D) + m<D = 90 degrees
6(m<D) = 90 degrees
m<D = 90 / 6 = 15 degrees.
JeanaShupp

Answer: m∠D=15°

Step-by-step explanation:

Given: ΔDEF is similar to ΔJKL .

In addition,  m∠F=90° and m∠K=5(m∠D)

Let m∠D = a

Then,

∠D=∠J=a

∠E=∠K=5a

∠F=∠L=90°

Using Angle sum property, in triangle ΔDEF, we get

[tex]\angle{D}+\angle{E}+\angle{F}=180^{\circ}\\\\\Rightarrow\ a+5a+90=180\\\\\Rightarrow\ 6a=90\\\\\Rightarrow\ a=15[/tex]

Hence, m∠D=15°

The angle sum property of a triangle says that, the sum of all the angles in a triangle is [tex]180^{\circ}[/tex].

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