The heat flux that is applied to the left face of a plane wall is q" = 20 w/m2. the wall is of thickness l = 10 mm and of thermal conductivity k = 12 w/m · k. if the surface temperatures of the wall are measured to be 50°c on the left side and 30°c on the right side, do steady-state conditions exist?

of course steady state condition occurs in almost any system but time it will occurs varies among system. for this kind of system, conduction, steady state conduction occurs when the temperature change from one point to the point is already constant. steady state is not achieved immediately because the heat travels and material will not be heated at the same way at the starting point.

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aristocles aristocles · Answer 2 · 2019-09-10T03:56:25+02:00

Answer:

given flux is very small then the above calculated value so it is not is steady state

Explanation:

As we know that heat flux is given in steady state by the formula

[tex]Q = \frac{k(T_1 - T_2)}{L}[/tex]

here we know that

[tex]T_1 = 50^o C[/tex]

[tex]T_2 = 30 ^o C[/tex]

k = 12 W/m k

L = 10 mm

now we have

[tex]Q = \frac{12(50 - 30)}{0.01}[/tex]

[tex]Q = 24000 w/m^2[/tex]

since given flux is very small then the above calculated value so it is not is steady state