There are 6 red marbles, 4 blue marbles, and 6 yellow marbles in a bag.

Two marbles are chosen without replacing them in the bag.

What is the probability that a red marble is chosen, followed by a blue marble?

Enter your answer as a fraction in simplest form, using the / symbol, like this: 42/53

Basically all you gotta do is 1/6 to represent the red marbles and you are only picking up one which is what that 1 represents in the numerator. Then, you have 1/4 to represent the one out of the blue marbles. You then multiply those two answers together to get 1/24.

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There are 6 red marbles, 4 blue marbles, and 6 yellow marbles in a bag. Two marbles are chosen without replacing them in the bag. What is the probability that a red marble is chosen, followed by a blue marble? Enter your answer as a fraction in simplest form, using the / symbol, like this: 42/53

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There are 6 red marbles, 4 blue marbles, and 6 yellow marbles in a bag.

Two marbles are chosen without replacing them in the bag.

What is the probability that a red marble is chosen, followed by a blue marble?

Enter your answer as a fraction in simplest form, using the / symbol, like this: 42/53