The magnitude of electric field intensity is [tex]6.24\times 10^{18}\;\rm N/C[/tex].
Electric Field Intensity
Electric field intensity can be defined as the force experienced by the unit positive charge placed at that point. In the mathematical form, the electric field intensity can be given as,
[tex]E = \dfrac {F}{q}[/tex]
Where F is the force, q is the charge and E is the electric field intensity.
Given
An electron experiences a 1.0-newton force. Then the charge on the electron is 1.602 x 10^-19C. Hence the electric field intensity can be given as below.
[tex]E = \dfrac {1}{1.602 \times 10^{-19}}[/tex]
[tex]E = 6.24\times 10^{18} \;\rm N/C[/tex]
Hence we can conclude that the electric field intensity is [tex]6.24\times 10^{18}\;\rm N/C[/tex].
To know more about the electric field intensity, follow the link given below.
https://brainly.com/question/26107515.
