If your'e looking to complete the square, then here's how you do it:
1.) Subtract 7 from each side: [tex] x^{2} -8x=-7[/tex]
2.) Take half of the value of B, which is 4, then square it to get C
3.) Now you should have [tex] x^{2} -8x+(4)^2=-7+(4)^2[/tex], because what you do to one side you have to do to the other
4.) Take the value of [tex] x^{2} [/tex] and 4, and plug them into an ordered pair: [tex](x-4)^2=9[/tex]
Now take the square root of both sides which is equal to [tex]x-4=[/tex]±[tex]3[/tex]
5.) Now subtract 4 from each side to isolate x: [tex]x=4[/tex]±3
6.) Solve: [tex]x=4-3[/tex] & [tex]x=4+3[/tex]
Final Answer: [tex]x=1[/tex] & [tex]x=7[/tex]
Hope this helps!!
