when 2x^2/y = w+2/4 is solved for w, one equation is

Answer: w= [tex]\frac{8x^{2} - 2y }{y}[/tex]
Step-by-step explanation:
From the question above, we have;
[tex]\frac{2x^{2} }{y} = \frac{w + 2}{4}[/tex]
We will have to make w subject of the formula. To do that we will first have to cross multiply
2x² × 4 = (w +2) y
8x² = (w + 2 ) y
we will now divide both-side of the equation by y
[tex]\frac{8x^{2} }{y}[/tex] = w + 2
we will then subtract 2 from both-side of the equation
[tex]\frac{8x^{2} }{y}[/tex] - 2 = w
We shall now make the left hand side of the equation a standard fraction
[tex]\frac{8x^{2} - 2y}{y}[/tex] = w
Therefore w = [tex]\frac{8x^{2} - 2y}{y}[/tex]