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Hello here is a solution :
The greatest common factor of 15u2v3, 20u5v2, and 45u3v5 is : 5u²v²
The greatest common factor of 15u2v3, 20u5v2, and 45u3v5 is : 5u²v²
Answer: [tex]5u^2v^2[/tex]
Step-by-step explanation:
Given monomials : [tex]15u^2v^3, 20u^5v^2, 45u^3v^5[/tex]
We can rewrite the above monomials as product below :-
[tex]15u^2v^3=5\times3u^2v^3\\\\ 20u^5v^2=5u^5v^2\times4\\\\45u^3v^5=5\times9u^3v^5[/tex]
Therefore, the greatest common factor for numerical coefficients of monomials = 5
Also, the greatest common power of u =2
and the greatest common power of v = 2
Hence, the greatest common factor of [tex]15u^2v^3, 20u^5v^2, 45u^3v^5[/tex] is [tex]5u^2v^2[/tex]