Answer:
Step-by-step explanation:
The given expression is
[tex]log_{6} (25)[/tex]
We use the following property
[tex]log_{a}(b)=\frac{log_{c}(b) }{log_{c}(a) }[/tex]
So,
[tex]log_{6} (25)=\frac{log(25)}{log(6)}[/tex]
But, [tex]log(25) \approx 1.40[/tex] and [tex]log(6) \approx 0.78[/tex]
Then,
[tex]log_{6} (25)=\frac{1.40}{0.78} \approx 1.80[/tex]
Therefore, a approximate value to the given logarithm is 1.80.
