Answer:
The vertex of the graph is (-3,2).
Step-by-step explanation:
We are given that an equation
[tex]y=-4(x+3)^2+2[/tex]
We have to find the vertex of given equation.
General equation of parabola along y- axis with vertex (h,k) is given by
[tex]y-k=a(x-h)^2[/tex]
[tex]y=a(x-h)^2+k[/tex]
Compare it with the given equation
Then, we get
[tex]h=-3, k=2[/tex]
Hence, the vertex of given equation is (-3,2).
