Respuesta :

By using Bhaskara's formula, we will see that the two solutions are:

  • x = 1.25
  • x = -6.25

How to solve a quadratic equation?

Here we have the equation:

x^2 = -5x + 8.

This is a quadratic equation, remember that for the general quadratic equation:

a*x^2 + b*x + c = 0

The solutions are given by Bhaskara's formula:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}[/tex]

We can rewrite our equation as:

x^2 + 5*x - 8 = 0

Using the above formula we get the solutions:

[tex]x = \frac{-5 \pm \sqrt{5^2 - 4*1*-8} }{2*1}\\\\x = \frac{-5 \pm 7.5}{2}\\\\[/tex]

Then the two solutions are:

  • x = (-5 + 7.5)/2 = 1.25
  • x = (-5 - 7.5)/2 = -6.25

If you want to learn more about quadratic equations, you can read:

https://brainly.com/question/1214333