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Two functions, A and B, are described as follows:

Function A
y = 8x + 3

Function B
The rate of change is 1 and the y-intercept is 4.

How much more is the rate of change of function A than the rate of change of function B?

1
7
8
9

Respuesta :

calculista

Answer:

[tex]7[/tex]

Step-by-step explanation:

we have

[tex]y=8x+3[/tex] -------> equation A

In the equation A the rate of change is equal to the slope m

[tex]m=8[/tex]

In the equation B

we have

[tex]m=1[/tex] ------> rate of change

[tex]b=4[/tex]

The equation B is equal to

[tex]y=mx+b[/tex]

substitute

[tex]y=x+4[/tex]

Find the difference of the rate of change of function A minus the rate of change of function B

[tex]8-1=7[/tex]

Answer:

7

Step-by-step explanation:

The standard model equation here is

y = mx+b

Now,

x and y are the variables

b is y-intercept, it means it is the value of y-coordinate on y axis where this line intercepts on y-axis

m = slope or rate of change or angle ∅ this line making with x -axis.

now arrange function A according to standard model equation

y = (8)x + 3

now, by comparison of standard and function A

m(A) = 8 and b(A) = 3

For function B

it is given that rate of change or slope is 1 and y-intercept is 4

so for function b

m(B) = 1 and b(B) = 4

Now question is about how much slope of function A is more than slope of function B

m(A)-m(B) = 8-1 = 7

So answer is 7.

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