Answer:
Option (b) is correct
[tex]^4P_2=12[/tex]
Step-by-step explanation:
Given: P(4,2)
We have to evaluate the value of P(4,2)
Consider the permutation P(4,2).
The possibility of choosing an ordered set of r object from n object is given by
[tex]^nP_r=\frac{n!}{(n-r)!}[/tex]
here, n = 4 and r = 2
Thus,
[tex]^4P_2=\frac{4!}{(4-2)!}[/tex]
Simplify, we have,
[tex]^4P_2=\frac{4!}{(2)!}=\frac{4\cdot 3\cdot 2!}{2!}=12[/tex]
Thus, [tex]^4P_2=12[/tex]
