Respuesta :
Since one equation has a positive y and the other a negative y we can simply add the two equations together to solve for x...
(4x-y=5)+(3x+y=16)
7x=21,
x=3, now you can use either original equation to solve for y...
3x+y=16 becomes:
3(3)+y=16
9+y=16
y=7
So the solution is the point (3,7)
(4x-y=5)+(3x+y=16)
7x=21,
x=3, now you can use either original equation to solve for y...
3x+y=16 becomes:
3(3)+y=16
9+y=16
y=7
So the solution is the point (3,7)
4x - y = 5
3x + y = 16
rearrange the first equation so you can substitute it into the second:
y = 4x - 5
3x + (4x - 5) = 16
3x + 4x - 5 = 16
7x = 16 + 5
7x = 21
x = 21/7
x = 3
4(3) - y = 5
12 - y = 5
-y = 5 - 12
-y = -7
-1(-y = -7)
y = 7
the answer is (3, 7)
hope this helps :)
3x + y = 16
rearrange the first equation so you can substitute it into the second:
y = 4x - 5
3x + (4x - 5) = 16
3x + 4x - 5 = 16
7x = 16 + 5
7x = 21
x = 21/7
x = 3
4(3) - y = 5
12 - y = 5
-y = 5 - 12
-y = -7
-1(-y = -7)
y = 7
the answer is (3, 7)
hope this helps :)