Respuesta :
Answer:
5 boxes and three pots
Step-by-step explanation:
Given : Zach has 53 flowers to plant.
He wants to plant them in groups of 10s and 1s
Solution :
Since there are 53 flowers
He wants to plant them in group of 10s and 1s
So , of 53 flowers There can be 5 groups of 10s and 3 groups of 1s
Since he can plot 10 flowers in each flower box.
So, there are 5 groups of 10s
So, there will be 5 boxes of flowers having 10 fowers each
Since 50 flowers used . 3 flowers left
they can plant one flower in pot
And there are 3 flowers left
So, pots will be 3
So, there will be 5 boxes and three pots
So, the 53 flowers can be arranged by making 5 boxes having 10 flowers in each box and 3 pots having one flower in each pot
There are 720 different ways the flowers can be planted
The number of flowers is given as:
Flowers = 53
Given that he wants to plant then in 10's and 1's,
- 50 of the 53 flowers can be planted in 5! ways
- The remaining 3 can be planted in 3! ways
So, the number of different ways the flowers can be planted is:
[tex]n =5! * 3![/tex]
Evaluate each factorial
[tex]n = 120 * 6[/tex]
[tex]n = 720[/tex]
Hence, there are 720 different ways the flowers can be planted
Read more about permutation and combination at:
https://brainly.com/question/8119212